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Q: What is the probability of getting a number greater than 4 When a fair die is thrown?

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the probability is 2/6 or 1/3

1 out of 6

1/3

3 out of 9

This is the same as 1 minus the probability that neither of them are greater than three. This is 1, minus the probability of getting greater than three, squared. Rolling higher than three has a 1/2 probability, so: P(at least one greater than 3) = 1 - (1/2)2 = 1 - 1/4 = 3/4

When a fair die is thrown the probability that a prime number will occur is 2:1

The probability is 146/1296 = 0.1127

The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.

If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4

There is a one out of six chance.

A die normally has 6 sides numbered 1 through 6. The probability of you landing on ANY number is 1:6, or you have a 1 in 6 chance of landing a 3.

1in 6 chance

It is 11/18.

When a Die is thrown then the probability of an event getting out-comes is not a prime number is 3/6. The possible prime numbers would be 2, 3, or 5. The possible outcomes are 1, 2,3,4,5 and 6. So 1,4 and 6 are not primes and there are 3 numbers out of 6 possible so that is 3/6 or p=.5

The probability of the outcomes is 1.

The probability is 8/36 = 4/9The probability is 8/36 = 4/9The probability is 8/36 = 4/9The probability is 8/36 = 4/9

If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.

Well, you have a 6-4, or 4-6 and a 5-5, that's the only rolls that will role a ten. Out of 6*6=36 possible rolls. so, 3/36.

None of the digits can be 10, so the probability is 0.

two dice are thrown once. write all the possible outcomes. find the probability of getting: (i) a total of 12 (ii) a total of 3 (iii) a total of 8

your chances of death are five times greater than if you are not thrown from the vehicle

A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.

P(score>3)=1/6+1/6+1/6=3/6=1/2

The composite numbers are 4 and 6; that is 2/6 of the numbers available. Therefore the odds on rolling such a number are "two out of 6" = 1/3 = 33.333%The 3 in that answer is recurring.Since the total of all probabilities which might occur in one event is 1.0 or 1 or 100%, it follows that the probability of not throwing a composite number is 4/6 = 2/3 = 66.66666666666666(recurring)%

Since there are only odd & even numbers, the probability is 1/2 or 0.5.