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Q: What is the lowest number which always leaves a remainder of one when divided by any of the numbers from two to ten?

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2521

Please help me my homework has this question and Im like OMG im in trouble if I dont do this!

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.

209

3

26

2

5

799

Because, by definition, an even number is one which leaves no remainder when divided by 2.

119

5.2

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11

18

It is a factor of that number and leaves no remainder

62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

Undefined: You cannot divide by zero

11

Suppose you want to find the gcf of 5040 and 1274. Make a list or a "ladder" starting with 5040 and 1274. Each item after that is the remainder of dividing the two numbers above. 5040 1274 1218 (5040 divided by 1274 leaves a remainder of 1218) 56 (1274 divided by 1218 leaves a remainder of 56) 42 (1218 divided by 56 leaves a remainder of 42) 14 (56 divided by 42 leaves a remainder of 14) 0 (42 divided by 14 leaves a remainder of 0). When you reach zero, the number before it (in this case 14) is the gcf. The gcf of 5040 and 1274 is 14. In general: Let a and b be the two numbers. repeat while (b >0) Let c = the remainder of a divided by b Let a=b Let b=c The gcf is a.

6172839

Numbers ending in 1, 3, 5, 7 or 9 are considered odd numbers.

Do you mean what, when divided by 2, leaves a remainder? That'd be any odd number (or fraction).

213 when divided by 5, 6, or 7 has a remainder of 3.

23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.

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