No. It cannot be. Mass cannot be measured in cm3, which is a measure of volume.
density = mass ÷ volume= 20 g ÷ 12 cm3≈ 1.67 g/cm3
The density of the mass is 48 g/cm3
The density of the 6 cm3 block of ice is approximately 0.67 grams/cm3. This can be calculated by dividing the mass (4 grams) by the volume (6 cm3).
density = mass ÷ volume = 30 g ÷ 10 cm3 = 3 g/cm3
5.0 L = 5000 cm31 L = 1000 cm3
m = dV (d for density (even though greek letter rho should be used))therefore m = (1.0 g/cm3)(5 L)m = (1.0 g/cm3)(5 dm3) (since 1 L = 1 dm3)m = (1.0 g/cm3)(5000 cm3) (since 1 dm3 = 1000 cm3)m = 5000 gm = 5 kg2,000 cm³
No. It cannot be. Mass cannot be measured in cm3, which is a measure of volume.
density = mass ÷ volume= 20 g ÷ 12 cm3≈ 1.67 g/cm3
Mass = [ gram ]Volume = [ cm3 ]Density = [ gram per cm3 ]
The density of the mass is 48 g/cm3
The density of the 6 cm3 block of ice is approximately 0.67 grams/cm3. This can be calculated by dividing the mass (4 grams) by the volume (6 cm3).
An object with a mass of 579 g and volume of 30 cm3 will have a density of 19.3 g/cm3.
The density of this copper mass is about 8.93 g/cm3
Density = Mass/Volume = 16.5 g / 2.2 cm3 = 7.5 g/cm3
Volume = Mass/Density = 600 g/3.00 g cm3 = 200 cm3
density = mass ÷ volume = 30 g ÷ 10 cm3 = 3 g/cm3