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The volume of the gold bar is not affected by such a physical deformation and remains at 525 cm3 and so the density is unchanged.
OK, we have you surrounded now! Where is the third gold bar?
From here, I can't quite make out the blocks of gold that you're looking at.But the density of gold is about 19.3 gm/cm3 , whether it happens to be a flake,a nugget, a coin, a bar, or an ingot. With density, size does not matter.
Density or weight is calculated by mass/volume
Bar lines divide the staff into measures
If both objects are pure gold then the density is the same. Weight and mass are not factors in this particular question.
Exactly the same.
Exactly the same.
If you use the definition of "density" as mass/volume, then yes. That's the standard definition.However, it is also possible to define density as weight/volume.
The density of the shiny, gold-colored bar of metal is 12.19 grams over cubic centimeters. The density of a Gold(Au) is 19.3 grams over cubic centimeters. These means that the gold-colored bar of metal is not pure gold.
If a bar of copper has a mass of 216g and a volume of 24 cm3 then its density is 9 g/cm.
Intensive properties depend only on the type of matter you're dealing with. For example, density: a single atom of gold will have the same density as a huge bar of gold, it doesn't matter how much of it there is. Extensive properties do depend on how much of the substance you have. A cubic centimeter of gold has more volume and mass than an atom of gold, so they are both extensive properties.
It depends on the density of the material of which the bar is made.
Sure, the density of pure gold would be greater than most other metallics, the density of gold is 19.32 g/mL, so anything less than that, and the bar would not be pure.
mass=density/volume
In the metric system, the Gram, as in kilogram is the standardfor mass measurement
The gold. The mass per unit volume of the gold will be much higher.