5
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
34 + 23 = 57
23
Mean (Average) means to add all the terms together, and then divide by the number of terms, which is '8'. ( 21 + 23 + 27 + 28 + 32 + 32 + 34 + 43) / 8 => 240/8 = 30 The Mean.!!!!
The mean absolute deviation is 8.22
49.30179172 is the standard deviation and 52 is the mean.
The standard deviation of 20 22 26 28 34: σ=5.4772
34° 23′ 5.71″ N, 109° 16′ 23.19″ E34.384919, 109.273108
34
23% of 34= 23% * 34= 0.23 * 34= 7.82
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
34 and -34.
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
mean median and mode of 28 54 34 50 34 First of all place the numbers in Rank Order. 28,34,34,50,54. I'll do then in reverse order. MODE ; is the number/term that is most frequent, which is '34'. MEDIAN : is to absolute middle number. Out of the five terms, the second '34' is the absolute middle term, so it is the median. MEAN : Is to summ all the terms and divide by the numbers of terms. Hence ( 28+34+34+50+54 ) / 5 = 200/5 200/5 = 40 THe mean.
Compute the variance (or its square root , standard deviation) of each of the data set. Set 1: standard deviation = 10.121 Set 2: standard deviation = 12.09 Set 2 shows more variation around the mean. Check the link below
57