Math and Arithmetic

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step 1. arrange the numbers in ascending order (from low to high) as follows.

was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64

now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80

step 2. count the number of the numbers above, or assign an index as follows.

string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80

index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

so the count is 20.

The mode is the number most frequently observed. The mode is 65, which occurs four times.

The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67.

Alternate methods:

1) Use Microsoft Excel statistical functions of =mode() and =median()

2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.

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0Mean: 83 Median: 62 There is no mode.

68 74 93 88 72 89 93 77 62

For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62

A single number, such has, 7152484654452062 can have only one mean, median, mode. And the range is 0.

One possible set is 62, 62, 75, 76 and 82

median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79

Lets define everything first. Minimum is 17 - lowest number is given. 17 ? ? ? ? ? ? range is 45 which means largest number is 17 + 45 = 62! 17 ? ? ? ? ? 62 median is 32 or middle number 17 ? ? 32 ? ? 62 mode is 41 17 ? ? 32 41 41 62 The last two numbers are up to you to choose as long as they are bigger than 17, smaller than 32, and are not the same number.

The median is the middle number when numbers are put in order. If there is an even amount of numbers, then it is the value half way between the two middle numbers. There are an even amount of numbers in this case. As both of them are 62, then the median is 62.

Range- the figure between one number and another. eg. the range between 10 and 14 is 4. so the sum is 14-4=4. Mean-the figure when all the numbers of A a sequence have been added up and divided by the number of numbers there. eg. 10, 24, 16, 12. the mean is 15.5 because 10 + 24 + 16 + 12 = 62 and 62 divided by 4 is 15.5. Median- when the numbers in a sequence are but in ascending order and the number in the middle is the median. eg. 12, 14, 17, 22, 24. the median is 17 because 17 is in the middle. Mode- the most common number in a sequence. eg. 20, 17, 2, 20, 26. the mode is 20 because it is the number that is most common (appears the most). Hope I've been of help. :)

range - 59 median- 35

The mean average is 51

59, 60, 60, 60, 62, 64, 65, 70, 71, 78 The median is 63.

mode is the highest amount frequencymean is when you add up all of the frequency and divide by how many pieces of data there arerange is highest freq. minus lowest freq. = the range xHope this helped x---------------------------------------------------------------------------------------------------Answer 2:Let's look at this random set of numbers:[ 1 1 3 5 7 8 9 11 17]The median of this set of numbers is 7, because it is the middle digit.The mode of this set of numbers is 1, because there are more 1's in the set compared to all other numbers.The mean of this set of number is 6.88. Mean is another word for average. To find the average of a set, add up all the numbers (1+1+3+5+7+8+9+11+17=62), and then divide by the total amount of numbers in the set. There are 9 numbers in this set, so 62/9= 6.88.The range of the set is the largest number (17) minus the smallest number in the set (1). So 17-1=16. The range is 16.

It is 31, the middle value when the are arranged in order.

The median is 72.5, which is the number halfway between the two middle numbers when they are arranged in order.

The median works out as 26 because (22+30)/2 = 26

Put them in order, least to greatest. 62, 78, 84, 89, 94, 94, 96, 98 The range is the smallest subtracted from the largest. 98 - 62 = 36 The range is 36. The median is the average of the middle two. 89 + 94 = 183 divided by 2 = 91.5 The median is 91.5

Median = 94 but that sure was a weird spelling test!

It is 31, the number in the middle when they are listed in order.

Then that number will be the median. For example, if your set is 4, 4, 19, 20, 23, 23, 23, 43, 62, 76 and 89, then the second 23 is the middle number, and so it is the Median.

To find mode first order your numbers from largest to smallest. 75, 62, 59, 49, 47. Now remove the biggest & smallest, and repeat until you have one number left. 75, 62, 59, 49, 47. 75, 62, 59, 49, 47. We're left with 59. So the mode of M{75,62,59,49,47} = 59.

85 is the median score.

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