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What is the mean mode median of 64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80?
64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
What is the mean of 61 65 67 68 68?
65.8
What are all the even numbers between 51 and 71?
52, 54, 56, 58, 60, 62, 64, 66, 68, and 70 are.
How do you calculate the varience?
find varience fo rthis numbers 71, 67, 70, 59, 71, 68, 67, 71, 80, 68, 74, 69, 72, 68.
What is the mean mode and median of this data 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64?
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
Multiples of 4 between 45 and 70?
48, 52, 56, 60, 64, 68
What number is between 45 and 68?
46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67
What are the multiples of 4 in between 50 and 80?
52, 56, 60, 64, 68, 72, 76.
What is 52 times 68?
52 x 68 = 3536
Which is greater 67 or 68?
68 is greater than 67.
What is 67 plus 1?
68
What is the ratio to 68 days to 52 days?
68 days/52 days = 68/52 = 17/13
