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Q: What is radical x times radical x?

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12 radical 6 x 6 radical 6 = 72 x 6 = 432

x√x=x^1.5

√2 x √2 = (√2)2 = 2

3 sqrt(6) x sqrt(6) = 18

√3 x √21 = √3 x √(3 x 7) = (√3 x √3) x √7) = 3√7

Radical (3x) = radical(x) * radical(3).

Because the radical cancels out the "x".

sqrt(3) x sqrt(15) = sqrt( 3 x 15 ) = sqrt( 45 ) = sqrt( 9 x 5 ) = 3 sqrt(5)

radical(14)*radical(2) = 2*radical(7) Without further information available we will consider only the square roots. The square roots of 14 are +3.741 and -3.741, similarly the square roots of 2 are+1.414 and -1.414 and so we can have four products 1) (+3.741) X (+1.414) = +5.155 2) (-3.741) x (+1.414) = -5.155 3) (+3.741) x (-1.414) = -5.155 4) (-3.741) x (-1.414) = +5.155 Expressions 1 and 4 are equal, expressions 2 and 3 are equal. Hence the product of radical 14 times radical 2 can be +5.155 or -5.155

1 over 2 times radical 6

radical 30

2 times radical 5 or about 4.472135955

4 x2

Square root of 3 is approximately 1.73, so 1.73 x 9.6 = 16.608

20

√18

3

97

98

integral of radical sinx

√x

2 radical 11 the square root of 44. 44/2 = 22 radical 2 x 22 radical 2 x 2 x 11 Since 2 is under the radical twice you can take it out 2 radical 11

sqrt 175 = sqrt 25 x sqrt 7 = 5 x sqrt 7

You can multiply the radicands together if the radical is the same. So, the answer is radical 13*17=radical 221

30