Q: What is the median of 76 54 92 88 75 93 92 68 88 76 76 88 80 70 88 72?

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Range = 47 Median = 70 Mode = 72 Mean = 68

Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.

71 is the median of those numbers.

70

The median is 78.

Median is: (54+72)/2 = 63.

It is 68, the number in the middle when they are arranged in order.

65 is the median,

76

43

The range is 72 minus 66 = 6

The average is 70.

It is 72, the middle number when they are arranged in order.

the median is 785

The median of those numbers is 78. There are 18 numbers and when they are in numerical order the two middle ones are 76 and 80, so halfway between them is 78.

It is: 69

I guess you mean: What is the median of the numbers 71, 67, 67, 72, 76, 73, 68, 72, 72? (because adding the numbers would yield a single number). The median is the middle number when the numbers are listed in order. Listing in order: 71, 67, 67, 72, 76, 73, 68, 72, 72 ⇒ 67, 67, 68, 71, 72, 72, 72, 73, 76 There are 9 numbers, so the middle number is the 5th one which is 72. If there had been an even number of numbers, there is no middle one so the median is the mean average of the middle two. Example: If there had been no 76, so the list contained: 67, 67, 68, 71, 72, 72, 72, 73 then there would be 8 numbers, so the median would be the mean average of the 4th and 5th numbers, namely: (71 + 72) ÷ 2 = 71.5

68 74 93 88 72 89 93 77 62

71. I think... (just kidding!)

Mode refers to the most commonly recurring number. In this case, both 68 and 70 appear twice. So, this set has two modes.

88

54, 56, 58, 60, 62, 64, 66, 68, 70, 72

to find the mean of a group of numbers, add them together and divide by the number of numbers there are in that group. in this case there are 6

The mean of the data is 80.

The median of (12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96) is 54.