The median average of a set of numbers is the middle number when the numbers are listed in order. If there is an even number of numbers then the median is the mean average of the middle two.
To find which is the median value add 1 to the number of items and divide by 2. If this is a whole number that is the median; otherwise the median is the mean average of the numbers that are at the whole part of this result and the next one:
The dataset {95, 95, 98, 98, 98, 101, 102, 103, 104, 104} has 10 items, so the median is the mean average of the middle two.
To find which is/are the median value::(10 + 1) /2 = 11/2 = 5.5 → the median is the mean average of the 5th and 6th items.
→ median = (98 + 101) ÷ 2 = 95.5
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∙ 7y agomean: 104.4 median: 104 mode: 104 range: 5
20,351.401 = (2 x 104) + (0 x 103) + (3 x 102) + (5 x 101) + (1 x 100) + (4/101) + (0/102) + (1/103)
(0/101) + (0/102) + (1/103) + (0/104) + (0/105) + (1/106)
30.2959 = (3 x 101) + (0 x 100) + (2/101) + (9/102) + (5/103) + (9/104)
0.0001 = (0 x 100) + (0/101) + (0/102) + (0/103) + (1/104)
trick question you getit when you are 101 102 103 or 104
75,478.987 = (7 x 104) + (5 x 103) + (4 x 102) + (7 x 101) + (8 x 100) + (9/101) + (8/102) + (7/103)
92,300.054 = (9 x 104) + (2 x 103) + (3 x 102) + (0 x 101) + (0 x 100) + (0/101) + (5/102) + (4/103)
mean: 104.4 median: 104 mode: 104 range: 5
400,400.404 = (4 x 105) + (0 x 104) + (0 x 103) + (4 x 102) + (0 x 101) + (0 x 100) + (4/101) + (0/102) + (4/103)
904.3005 = (9 x 102) + (0 x 101) + (4 x 100) + (3/101) + (0/102) + (0/103) + (5/104).
4 × 104+5 × 103+2 × 102+7 × 101+0 × 100
7*104 + 4*103 + 2*102 + 7*101 + 1*100
Ruthenium isotopes are: Ru-96, 98, 99, 100, 101, 102, 103, 104, 106.
#101 Roxy #102 Lady GooGoo #103 Blingo #104 Dustbin Beaver
70,340.50 = (7 x 104) + (0 x 103) + (3 x 102) + (4 x 101) + (0 x 100) + (5/101) + (0/102)
20,351.401 = (2 x 104) + (0 x 103) + (3 x 102) + (5 x 101) + (1 x 100) + (4/101) + (0/102) + (1/103)