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60 63 68 80 91 91 100?

First place the terms in Rank Order.

NB This has already be done.

For the median you take the ABSOLUTE middle term.

Which in this case is '80'.

Notice there are three terms to the left of '80' and three terms to the right.

NNB This is good for an odd number of terms.

When there is an even number of terms , you take the middle two terms . Add then together and divide by '2'.

Do for the above set of terms , we add an eighth term , say '110'.

Then

60 63 68 80 91 91 100,110.

We take the two middle terms '80' & '91'(80+ 91) / 2 = 85.5 ; rthis is the median term.

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The median is 80, the middle number when they are listed in order.

Q: What is the median of this set of numbers 60 63 68 80 91 91 100?

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it is 1000000 i dont know but face

Irrational numbers.

2,5,10,1

10 60 and 100 are not included in the range, so 9

59, 60, 60, 60, 62, 64, 65, 70, 71, 78 The median is 63.

Related questions

Median of the set = arithmetic mean of 75 and 85 = 80

100, as it is the middle value of the numbers.

it is 1000000 i dont know but face

Add all of the numbers together (find the sum of the set) 50 + 60 + 70 + 80 + 90 + 100 = 450. Then divide the sum by the amount of numbers in the set (6); 450 / 6 = 75.

The median of a single number, such as 45603456209034, is the number itself.

The median is 60.

Irrational numbers.

It is: 60*100 = 6,000

It is: 69

30 and 60, among others.

Yes

To find the mean, add up the numbers in the set and divide that total by 22 (the number of numbers there are) In a set with an even number of numbers, the median is the average of the middle two which appears to be 69.25 Since no number appears more often than any other, this set has no mode.