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Q: What is the missing number in this sequence 1 8 27 125?

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64 should be in between 27 and 125.

64

64 because it is basically cube each number in a row.

64

125

64 should be between 27 and 125. (1 cubed equals 1. 2 cubed equals 8. 3 cubed equals 27. 4 cubed equals 64. Etc.)

125 (the sequence is successive numbers cubed)

64.The first number is 1 cubed, the second is 2 cubed, the third is 3 cubed, etc.

125 (each number is increased by the exponential 3n from the previous: +1, +3, +9, +27, +81)

64, it's a list of cubes

256

The missing number in this sequence is 64, or 4 raised to the third power. You find the answer by noting that each number in the sequence is a counting number starting at 1 that is raised to the third power. For example, 2 raised to the third power (2 x 2 x 2) is 8.

These numbers are cubes of the numbers 1,2,3,5 & 6, respectively. So 43 is missing, which is 64. It should go between 27 and 125.

Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.

343

343.

The answer depends on where, within the sequence, the missing number should have been.

64 It is a series of cubes 13, 23, 33, 43, 53 etc

64 because the series is 13, 23, 33, 43, 53, 63

64 is missing; the numbers are cubes of 1,2,3,4,5,& 6.

327

64 because each number is cubed

It is hard to know exactly what sequence was typed in as Answers removed all punctuation including commas and any question mark not at the end of the question asked; there may have been commas between digits or numbers, or the "sequence" may have been the single number as it appears. As a single number I can see 6 and 4 missing between the 7 and 1 and a 2 missing between the 5 and 1, making the number 182764125216 which is the first 6 cube numbers (1, 8, 27, 64, 125, 216) strung together. The question make have been 1, 8, 27, ??, 125, 216 (entered with the '2' of the '216' accidentally missed out), in which case the missing number is 64; again the sequence is the first 6 cube numbers.

13 ...23 ...33 ...43 ...53=125■

64 Each term number is cubed: 43 = 64