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Molarity = moles of solute/volume of solution

so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl)

= 2.1389 moles NaCl/400 Liters

= 0.00535 M NaCl

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โˆ™ 2010-06-18 22:30:55
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Q: What is the molarity of a solution that contains 125 g of nacl in 400 l of solution?
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Related questions

What is the molarity of a solution that contains 125 g NaCl in 4.00 L solution?

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What is the molarity of a solution that contains 125 g NaCI in 4.00 L solution?

Molarity is moles per litre, however we have 4 litres. So we have to divide 125 by 4 first. 125/4 is 31.25 grams. The molecular weight of NaCl is 58.443g/mol so the overall molarity is 0.53471 molar.


What is the molarity of a solution that contains 125 g NaCl dissolved in 4.00 L of solution?

The gram formula mass (for an ionically bonded compound such as NaCl, the counterpart to a gram mole for covalently bonded compounds) is 58.44. Therefore, 125 g of NaCl constitutes 125/58.44 or about 2.1389 gram "moles". Since molarity is defined as the ratio of moles of solute dissolved to total volume of solution, the given solution is 0.535, to the justified number of significant digits.


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What is the molarity of a solution10.0g of acetone C3H6O in enough water to make 125mL of solution?

The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution


What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?

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What is the percentage of a 1 to 125 solution?

The percentage of a 1 to 125 solution is simply 1/125 or 0.008 or 0.8%.


How many moles of KOH are dissolved in 125 mL of 0.500 M KOH?

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