4.32
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
Heating contribute to the water evaporation.
An *aqueous* solution is formed when a substance is dissolved in water. The term "aqueous" stands for the latin word "aqua" which means water.
POSSIBLE ANSWER: nickel (Ni) EXPLANATION: all metals dissolve in water more or less and there is an equilibrium point at which the dissolving rate and the condensing rate are the same. If the solution already has enough nickel ions (in other words it is a saturated solution), then the solid nickel you put in will not dissolve.
The molarity is 0,031.
Aqueous refers to water, so the liquid in an aqueous solution is water.
0.17 Molar
You need to convert to g/litres first. 40/1.5 is 26.6667g. The molecular weight of glucose is 180.156. 26.66667/180.156 is 0.148 molar.
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
1.3M
0.0554 M
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
100 g of solution containing 50 g of NaOH.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
Heating contribute to the water evaporation.