0,98
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
20%
The mixture water-ethanol is homogeneous.
1. Extract 959,6 mL from the 99 % solution. 2. Add 40,4 mL water.
Pure ethanol is slightly basic- about 7.9 However, a solution of ethanol and water is about 7,0- neutral
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
0.375
20%
The mixture water-ethanol is homogeneous.
The answer is 31,05 g ethanol.
Unless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.
1. Extract 959,6 mL from the 99 % solution. 2. Add 40,4 mL water.
Add 10 parts water to 90 parts 100% ethanol.
Percent by Volume of Solute in Solvent = Volume Solute/ (Volume Solvent + Volume Solute) * 100% = 48/ 192 = 25%
Volume percent (v/v %) is defined as: volume percent = [(volume of solute) / (volume of solution)] x 100% Volume percent is handy when preparing solutions of liquids. Concentration of a solution can be stated in volume percentages. Be aware that volume of solution is in formula denominator, not volume of solvent. Thus to get 10% v/v solution of ethanol in water you can take 10 ml of ethanol and add enough water to have total 100 ml of resulting solution. It is worth to mention volumes of solute and solvent cannot be simply added to get volume of solution. For instance if you add 10 ml of ethanol to 90 ml of water the volume of the solution will be less than 100 ml.
Pure ethanol is slightly basic- about 7.9 However, a solution of ethanol and water is about 7,0- neutral
Almost no salt will dissolve in pure ethanol. If salt is added to a solution of ethanol and water, which are miscible, it may form a homogenous solution without being stirred.