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The multiplicative inverse is when you multiply a certain number, and the product is itself, the number. So, the multiplicative inverse of 8 is of course, 1. For every number, the multiplicative number is 1, because a certain number times 1 is equal to the certain number. It's simple!!

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12y ago
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12y ago

the multiplicative inverse of -8 is just positive 8 :)

* * * * *

NO, that is the additive inverse. The multiplicative inverse of -8 is -1/8 or -0.125

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12y ago

1/8 or 0.125

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Q: What is the multiplication inverse of 8?
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Related questions

What is the inverse of mult ipacation?

The inverse of multiplication is division, such that:8 x 9 = 7272 / 9 = 872 / 8 = 9.


What is the difference between the inverse of addition and the inverse of multiplication?

the inverse of addition is subtraction and the inverse of multiplication is division. Of course, multiplication is just repeated addition so division is just repeated subtraction!


What is the inverse operation of addition and multiplication?

The inverse operation of addition is subtraction. The inverse multiplication by a number other than 0 is division. Multiplication by 0 does not have an inverse operation.


What is the inverse of subtraction?

Addition is the inverse of Subtraction. Division is the inverse of Multiplication. and then visa-versa. :-) Addition is the inverse of Subtraction. Division is the inverse of Multiplication. and then visa-versa. :-) the Answer is subtraction


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The inverse of multiplication is division.


Why are multiplication and division inverse?

They are inverse because they are the opposites.


What is another name for a multiplicative inverse?

The inverse of multiplication is division. * * * * * The inverse of the operation of multiplication is division, as stated in the above answer, but another name for the multiplicative inverse is a reciprocal.


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this is no Inverse property for multiplication


Inverse of multiplication?

Division.


What is the Inverse of division?

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What is the multiplication inverse?

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What is a inverse of division?

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