-9
The numbers are increasing in line with the 3 times (multiplication) table.6-7 is plus 1.7-10 is plus 3.10-16 is plus 6.16-25 is plus 9.Next in the 3 times table is 12. So, the next number will be 25 + 12.The answer is 37.
100
10 and 11
-8 minus 10 -8 plus 10
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
(-10) + (-7) + (-14) = -31
The numbers are increasing in line with the 3 times (multiplication) table.6-7 is plus 1.7-10 is plus 3.10-16 is plus 6.16-25 is plus 9.Next in the 3 times table is 12. So, the next number will be 25 + 12.The answer is 37.
13
Look at the multiplication table. 5, 10, 15 ...
100
It is not! There is not an efficient form of multiplication to add 3 to 7.7*(13/7) = 10 can hardly be described as a more efficient operation!
Um, not sure how to do that, but you can create a sort of "table" in C++ by using multidimensional arrays. Below is an example of how to create a two-dimensional array: int myArray[10] [10]; You can add more dimensions to the array in order to increase its storage capacity.
10 and 11
-8 minus 10 -8 plus 10
5, 10, 15, 20, 25, 30, 35, 40
The answer depends on how far the multiplication table goes. Some people learn them to times 10, others to x12 and some to x15.
199