the water displacement method
It depends on what the second method is!
A beaker. Simply fill the beaker with a known quantity of liquid. Drop the object into the beaker, and measure the difference in the fluid levels.
Because only regular-shaped objects have a consistent length, width, height, and shape. When dealing with an object composed of differing shapes, your must calculate each portion separately and then add them. For instance, if you have a swimming pool of two depths and want to determine cubic feet, you would have to calculate the volume for each section and then add them.
He discovered the method to calculate the volume of a irregular object (rock).
An L shaped figure is a plane figure and so will not have a volume.
Use volume displacement method.
It depends on what the second method is!
Mass divided by Volume = Density. Or use the displacement method for an irregularly shaped object.
It is the displacement method.
Google "Archimedes' Principle" and see if that gives you a clue...
Half fill a graduated glass beaker with water and note the level. Place irregularly shaped object into the beaker. Note the new level. The difference between the two levels is the volume of the object. cw: OK, that method works for objects that don't get wet -- like steel. Tissue paper would not be a good candidate. Also, if the object floats, you have to submerge the object.
Immerse the object completely in a liquid (e.g. water) and measure the volume of liquid displaced.
It is used to find the volume of an irregularly shaped object. An object dropped into a volume of water will displace an equal volume of water.
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
method usede to figure the volume of an irregular shaped object
When you are trying to find the volume of an irregularly shaped object.
Volume displacement.