785. sequence multiplies number by 5 then minuses 3 on next go and repeats
REEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
3
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3
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d-ik-
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160
20000 / 5 = 4000 4000 / 5 = 800 800 / 5 = 160 160 / 5 = 32
It depends on whether there are to be added, multiplied or something else. How about 1+2+157?
The rest of the sequence would be as follows: 40, 20, 10, 5... because each successive number is half of the prior.
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.The simplest rule for the given sequence of numbers is Un = 7*n - 1 so that U6 = 41.
151, 157.
How about: 157
40 5 10 20 40 80 160.......double the number each time.
160
160
160
Yes, each number is multiplied by 2 therefore the next 2 numbers in the sequence would be 80 & 160
74, according to the rule: Un = (3n4 - 38n3 + 177n2 - 270n + 160)/8, where n = 1, 2, 3, ...
The 40th number in the sequence will be 40 x 4, or 160.Reasoning:Because the sequence is multiples of 4.The 1st number in the sequence is 1 x 4, or 4.The 2nd number in the sequence is 2 x 4, or 8...The 4th number in the sequence is 4 x 4, or 16...The 17th number in the sequence is 17 x 4, or 68
151 157.
That's the prime factorization of 160.
13 x 13 = 169