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The sequence is generated using cubes, or n^3. The next number in the sequence will be 4^3, or 256.

Q: What is the next number in this sequence 1 8 27?

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125 (the sequence is successive numbers cubed)

27

327

81 Each number is 3 x the previous number. So, 3 x 27 = 81.

Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.

Related questions

125 (the sequence is successive numbers cubed)

243

64. It's the sequence f(n) = n^3

343.

27

27

327

27

81 Each number is 3 x the previous number. So, 3 x 27 = 81.

Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.

The next number in the sequence is 27. To get the next number, double the number and add one. Except for the second number, all the numbers in the sequence follow this rule.

13 ...23 ...33 ...43 ...53=125■