Q: What is the next number in this sequence 1 8 27?

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125

64. It's the sequence f(n) = n^3

125 (the sequence is successive numbers cubed)

243

343.

27

327

27

81 Each number is 3 x the previous number. So, 3 x 27 = 81.

The next number in the sequence is 27. To get the next number, double the number and add one. Except for the second number, all the numbers in the sequence follow this rule.

13 ...23 ...33 ...43 ...53=125■

Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.

1 3 8 27 32 1x3 =3 3+5=8 8x3=27 27+5=32

The next one is 125.

39

81

81

This is a peculiar number sequence which follows the following rule: +7, -4, +8, -3, +9, -2... The next few functions would be +10, -1, +11, -0 And thus the next few numbers in the sequence would be 17+10=27, 27-1=26, and so on. The sequence in total goes 2, 9, 5, 13, 10, 19, 17, 27, 26, 37, 37.

The answer is 137, it is obtained like this:0 + 26 + 1 = 2726 + 27 + 1 = 5427 + 54 + 1 = 8254 + 82 + 1 = 137

The next number is 4, followed by -2

1

25 is the next number that appears in that sequence.

27

16 is the next squared number.

The next number in the sequence is 18. It's +1, +2, +3, +4, ....