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Q: The sum of a number and 8 is less than 12?

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you are the number 48

6

56. Tens digit is greater than 4 and less than 6 so it can only be 5, so the number is 5X. It is one less than the number whose digits sum to 12, so its digits sum to 12-1 = 11 → 5 + X = 11 → X = 11 - 5 = 6 → the number is 56.

44 and 32

The sum of the prime numbers greater then 2 and less than 12 equals 26

They are 7 and 5.

12 and 26

12

57

x+8=20+12

21 > 3x + 12 < n +5

N = -12 + 8*(17+28) = -12 + 8*45 = -12+360 = 348

48

I assume you mean the sum of the digets equal 12. In that case your problem has only one solution and that is 39. No other number satisfies those criteria

43

12 and 56

It is (12 + 6) - 7

-5

-6

810

390 480 570

The sum of the factors of 10 (excluding itself) is equal to 1 + 2 + 5 = 8. Therefore, since its factor sum is less than the number itself, 10 is a deficient number. The lowest abundant number is 12.

The sum is: 12+14+15+16+18 = 75

The fact that the sum of its proper divisors is greater than 12.

It is: 19-7 = 12

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