According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. The simplest solution, based on Un = 4*(n + 2) for n = 1, 2, 3, ... is 32.
12 + (n - 1) x 4
Another Answer:- nth term = 4n+8 and so the next term will be 32
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
8 + 4n
The nth term of the sequence is expressed by the formula 8n - 4.
The nth term of this sequence is 3n + 4
28 - 8n
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
Un = 29 - 9n
It is: nth term = 6n-4
The nth term of the sequence -4 4 12 20 29 is 8n+12 because each time the sequence is adding 8 which is where the 8n comes from. Then you take 8 away from -4 and because a - and - equal a + the answer is 12. Which is where the 12 comes from. Hope I helped.
They are: nth term = 6n-4 and the 14th term is 80
12, 20, 28, 36, 44
The nth term is: 3n+2 and so the next number will be 20
[ 6n + 8 ] is.
here t1=2 t2=6 t3=12 t4=20 t5=30 the nth term is n(n+1) for t1 = 1(1+1)=2 for t2=2(2+1)=6 for t3=3(3+1)=12 for t4=4(4+1)=20 for t5=5(5+1)=30 for tn=n(n+1)
It is: 26-6n
Tn=4n+16 If you see, it goes like 20, 24,28,..... So, Tn is just equal to 20+(n-1)4, with first term=20, common difference=4
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
The (n)th term = the (n - 1)th term + (2n + 1)
The nth term is 2n So the 20th term is 2 x 20 = 40.
20 - (3 * (n - 1))