The common difference (d) between successive terms is -9.
The first term (a) is 26
The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d.
Inputting the values for a and d gives :-
a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
It is: nth term = 35-9n
It is: 26-6n
Look at the differences bettween the terms: 9-2=7, 5-9=-4, 13-5=8, 10-13=-3The differences finally are: 7,-4,8-3,9,-2. The next difference must be 10, so the next term is 27(27-17=10) and the next difference must be -1, so the next term must be 26(26-27=-1). Finally, the sequence is: 2 9 5 13 10 19 17 27 26 and so on.
The sequence S = 2, 2, 4, 6, 10, 16, 26, ... is the Fibonacci sequence multiplied by 2. Like the Fibonacci sequence, each term is found by adding the two previous terms, so Sn = Sn-1 + Sn-2.
The simplest rule is Un = 26 - 8n for n = 1, 2, 3, ... but it is always possible to fit a polynomial of degree 5 to the given sequence of numbers along with any sixth number.
It is: nth term = 35-9n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: 26-8n
It is: nth term = 7n-9
It is: nth term = 6n-4
Tn = 10 + n2
t(n) = 4n2 - 4n + 2
One method is an = n2 +1.So the first term is 1+1the second is 22 +1=5the third is 32 +1=10the fourth is 16+1=17 etc.There is also a recursive way to find it. I only point it out so you can see there may be more than one way to denote the nth term in a sequence. This method uses recursion.2+0=2=a12+3=5=a25+5=10 =a310+7=17 =a417+9=26 =a526+11=37 =a6So nth term is easy recursivelynth term=an =an-1 +(2(n-1)+1) =an-1 +(2n-1) =for example n=4 is the 4th term.a4 =a3 +(8-1)=10+7=17the 5th term a5 =17+(2x5-1)=17+9=26
you can find the rest of the numbers in the sequence by using inductive reasoning or noticing a pattern 26 , 17 , 8 , -1 , -10 it appears that you are subracting 9 each time. 26-9=17 17-9=8 8-9=-1 (8-9 changes to 8+-9 if you need to see that step) -1-9=-10 (-1-10 changes to -1+-9 if you need to see that)
46n9
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
[ 6n + 8 ] is.