One method is an = n2 +1.
So the first term is 1+1
the second is 22 +1=5
the third is 32 +1=10
the fourth is 16+1=17 etc.
There is also a recursive way to find it. I only point it out so you can see there may be more than one way to denote the nth term in a sequence. This method uses recursion.
2+0=2=a1
2+3=5=a2
5+5=10 =a3
10+7=17 =a4
17+9=26 =a5
26+11=37 =a6
So nth term is easy recursively
nth term=an =an-1 +(2(n-1)+1) =an-1 +(2n-1) =
for example n=4 is the 4th term.
a4 =a3 +(8-1)=10+7=17
the 5th term a5 =17+(2x5-1)=17+9=26
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: 26-8n
It is: nth term = 6n-4
Tn = 10 + n2
t(n) = 4n2 - 4n + 2
It is: nth term = 35-9n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
It is: 26-8n
It is: nth term = 7n-9
It is: nth term = 6n-4
Tn = 10 + n2
t(n) = 4n2 - 4n + 2
you can find the rest of the numbers in the sequence by using inductive reasoning or noticing a pattern 26 , 17 , 8 , -1 , -10 it appears that you are subracting 9 each time. 26-9=17 17-9=8 8-9=-1 (8-9 changes to 8+-9 if you need to see that step) -1-9=-10 (-1-10 changes to -1+-9 if you need to see that)
46n9
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
[ 6n + 8 ] is.