If you're asking what the nineth erm is, it's 58. The pattern is to add 7 to a umber to get the next number. 2+7=9, 9+7=16, 16+7=23, and so on.
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2
2n +29
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The nth term is 7n-5 and so the 6th term will be 37
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
We note that the numbers rise by addition of ;7;7 between terms. Hence we can write 7n . The first term( n- 1) is '9' So we can write 7(1) + c = 9 7 + c = 9 c = 2 So the nth term becomes 7n + 2
If you meant: 2 12 22 32 then the nth term = 10n-8
9 ,16 ,23, 30 We note that there is a difference of '7' between terms. So the first part of the 'nth' term is 7n. Note the '7' becomes multiple. Next we need to find the constant 'c' So taking the first term (n = 1) we write. 7n + c = 9 7(1) + c = 9 7 + c = 9 c = 2 So the 'nth' term is '7n + 2' To verify , try the 3rd term n= 3 then answer should be '23'. 7(3) + 2 = 21 + 2 = 23 As required.
The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2
2n +29
14+9n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 9n+5 and so the next term is 50
It is: 10n-7 and so the next term is 43