tn = 4 + (3/2) n (n - 1)
= (3n2 - 3n + 8) ÷ 2
Ans:49.
4+3=7
7+6=13
13+9=22
22+12=34
34+15=49.(we are adding multiples of 3 to the next consecutive terms).
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It is: nth term = 29-7n
The nth term is 5n-3 and so the next term will be 22
5
The nth term is -7n+29 and so the next term will be -6
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
It is: nth term = 29-7n
The nth term is 5n-3 and so the next term will be 22
6n+10
5
The nth term is -7n+29 and so the next term will be -6
The nth term is 3n+7 and so the next number will be 22
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
tn=5n-3
+9
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
The nth term of an arithmetic sequence is given by. an = a + (n – 1)d. The number d is called the common difference because any two consecutive terms of an. arithmetic sequence differ by d, and it is found by subtracting any pair of terms an and. an+1.