By varying the parameters of a quartic polynomial, the nth term can be made whatever you like.
But, taking the simplest solution,
Un = 2 - 4n for
?
They are: nth term = 6n-4 and the 14th term is 80
3n-2
It is: 26-6n
t(n) = (-5n4 + 62n3 - 247n2 + 334n - 36)/6
It is: -6n+22
It is: nth term = -4n+14
It is: 26-8n
f(n) = 14 - 6n -6n+20
It is: nth term = 6n-4
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
Tn = 10 + n2
The nth term is (2n - 12).
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
They are: nth term = 6n-4 and the 14th term is 80
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
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