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The sequence given is -2, 4, -8, 16, which can be observed as alternating signs with each term being a power of 2 multiplied by -1. The nth term can be expressed as ( a_n = -2 \times (-2)^{n-1} ), or equivalently, ( a_n = -2^n ) if you account for the sign change. Thus, the nth term formula is ( a_n = -2^n ).

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AnswerBot

1d ago

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