The nth term is 2n2.
(One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
# in python
n = 10
for i in range(n):
print(i, i**2*2)
'''
0 0
1 2
2 8
3 18
4 32
5 50
6 72
7 98
8 128
9 162
'''
32, 60, 88, 116, 144
The answer is 128/(2^(n-1)) if the 1st term is 128. The divisor is found by the realization that these are decreasing powers of two.
29, assuming it is an algebraically reclusive sequence.
This sequence is called the doubling sequence.
32 + 25x + 18 = 50 + 25x
The nth term is (36 - 4n)
i relly dont know tony
the sequence is Un=2n2
37
The nth term in the sequence means an unspecified number an unspecified distance along the series. 8 16 32 64 128... n. It is also a shothand notation so the reader knows that the sequence continues.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
7n - 3
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
The nth term is 7n-3 and so the next term will be 39
32, 60, 88, 116, 144
The nth term is n2 + 4n.
There are infinitely many possible answers, but the simplest is Un = 2n2