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Does area measure the number of square unit's that cover an objects surface?
yes
How do you find the area of a irregular quadrilateral without breaking it apart?
I do not believe that it can be done. You can get an estimate using either of the following methods:Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square. Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside†and “approximately half†but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
What is the definition of a square unit?
A square unit is a unit when squared equals a perfect square number. 5 is a square number, five times five is 25. Divid or square root 25 and you get 5. now technicaly every number is a square number but it is generally considered only whole numbers.
How do you find area compound shape?
The answer depends on the nature of the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together.For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina.Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses.That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square.Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unitArea of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape.Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about "mostly inside" and "approximately half" but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
How could you determine the area of a shape without a formula for that shape?
The answer depends on the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together.For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina.Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses.That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square.Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unitArea of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape.Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside” and “approximately half” but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
Does area measure the number of square unit's that cover an objects surface?
yes
How do you find the area of a irregular quadrilateral without breaking it apart?
I do not believe that it can be done. You can get an estimate using either of the following methods:Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square. Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside†and “approximately half†but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
How do you square footage?
Square footage is a measure of area. There are formulae for some simple shapes but for more complicated shapes there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids. Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square. Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside†and “approximately half†but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
Does the area of a shape have to be called a square unit?
Yes.
How can we measure the area of an irregular shape - jaytee 5 a?
The answer depends on the nature of the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together. For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids. Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square. Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside” and “approximately half” but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
What is the definition of a square unit?
A square unit is a unit when squared equals a perfect square number. 5 is a square number, five times five is 25. Divid or square root 25 and you get 5. now technicaly every number is a square number but it is generally considered only whole numbers.
What is the perimeter of a square if the area is ten inches?
The area of any shape should be in SQUARE unit, and not only unit. So the question is wrong!
What is the number of a square unit needed to cover a surface?
The units may be any squared units. It is an area. They may be square inches, feet, yards, miles, metres, kilometres etc.
How do you find an area of an irregular heptagon?
With difficulty. There are some aids that will enable you to do that but otherwise there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina.Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses.That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square.Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unitArea of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape.Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about "mostly inside" and "approximately half" but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
How do you find area compound shape?
The answer depends on the nature of the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together.For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina.Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses.That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square.Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unitArea of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape.Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about "mostly inside" and "approximately half" but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
Find square footage of odd shape?
The answer depends on the nature of the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together. For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about "mostly inside"Â and "approximately half"Â but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
How do you find the square feet for improper area?
The answer depends partly on the nature of the complex shape. Some complex shapes can be decomposed into smaller shapes whose areas can be determined using standard formulae. It is then simply a question of adding the parts together.For more complicated shapes, there are essentially two options: you can either use uniform laminae and mass or estimate the area using grids.Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina.Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses.That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square =Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unitArea of Shape = Mass of Shape/Mass of Unit Square.Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape.Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about "mostly inside" and "approximately half" but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
