It is x - y + 2 = 0
X squared is not an inverse function; it is a quadratic function.
∫ f'(x)/[f(x)√(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.
squared 3
5
square root of x/pi
8
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
X squared is not an inverse function; it is a quadratic function.
Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.
The Distance Formula! D = square root of (y2-y1) quantity squared + (x2-x1) quantity squared
∫ f'(x)/[f(x)√(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.
This expression factors as x -1 quantity squared.
squared 3
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
a quantity multiplied by itself
one quantity varies directly as the square of the other quantity. in symbols, y = kx squared
They are at x = -3 and x = -2.