conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++
When the operator "plus" is defined in a non-standard way.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". There is no operator visible between the two numbers.
Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and resubmit. There is no operator visible before the final 9 in the expression which is to be factorised.
x^2 + 4x + 5 cannot be factored because its discriminant is less than zero.
It is not possible to answer the question since the inequality symbol cannot be viewed.
comma (,) is an example
1. Member-of operator (.) 2. Pointer-to-member-of operator (.*) 3. Ternary condition operator (?:) 4. Scope resolution operator (::) 5. sizeof operator 6. typeid operator
No.
The only "special" operators in C++ are those that cannot be overloaded. That is; the dot member operator (.), pointer to member operator (.*), ternary conditional operator (:?), scope resolution operator (::), sizeof() and typeof().
No, there is no such operator or function in Java that can tell you the amount of memory an object uses.
C++ and Java are identical except for...No pointers in JavaAll object names are referencesNo operator ->, only operator .No multiple inheritance in JavaNo template classes in JavaThe run-time and class libraries are vastly different
Yes!Visual Java plus plus and Java Builder is different from the Java language?
Every languages are different, a C++ compiler cannot compile a Java source.
You cannot since there is no visible operator before the last number.
The if statementex.if (index < 5)printf("Index is less than 5\n");elseprintf("index is greater or equal to 5\n");(You can also replace the "if" with a "?" and the "else" with a "?" -- no, that would be syntax error)
Java
calloc operator,malloc operator