(1) x+y=15
(2) 4x+3y=38
From (1) one gets x=15 -y, put into(2)
4(15-y)+3y=38
60-4y+3y=38
60-y=38
y=22 then x=15-y=-7
(-7,22) is the solution
(5,3)
The ordered pair is (6, 3).
(0,7)
It equals 285
x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)
(5,3)
The ordered pair is (6, 3).
(0,7)
It equals 285
45
x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)
-15
30
The solution pair is (-7, 22), demonstrated as follows: (1) x + y = 15 : given; (2)4x + 3y = 38 : given; (3)3x + 3y = 45 : equation (1), multiplied by 3; (4) x = -7 : equation (2), minus equation (3); (5) y = 22 : equation (1), minus equation (4).
-9
15 plus -3 equals 12 12 divided by -6 equals -2
8 plus 15 = 23