Top Answer

9-2=7, 23-9=14, 51-23=28, 107-51=56. therefore, since the next number in the sequence will be twice the previous difference, it will be 107+112 which is 219

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2Start by adding 7, then add 7x2, then 7x4, then 7x8, etc. 2 + (7x1) = 9 9 + (7x2) = 23 23 + (7x4) = 51 51 + (7x8) = 107 The next number is 219.

107 double difference each time 2 + 7 = 9 9 + 7 + 7 = 23 23 + 14 + 14 = 51 51 + 28 + 28 = 107

61, 23, 97, 41, 67 yes. 51, 93, 39, no.

The prime numbers from 1 to 51 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47.

The Highest Common Factor (HCF) of the two numbers is 3. 63/3 = 23 and 51/3 = 17.

{| |- | 78 69 60 51 42 33 |}

To get the (mean) average, add them up and divide by 3 [since there are 3 numbers]: 12 + 16 + 23 = 51, and 51 Ã· 3 = 17.

5x+33=112x-51, deduct 5x from each side of the equation leaves 33=107x-51, add 51 to each side leaves 84=107x, divide both sides by 107 gives answer x=84/107

29, 61, 23, 97, 41, and 67 are prime. 81, 51, 93, 77, and 39 are composite.

51 is composite. 51 = 3 x 17. The other three numbers are prime numbers.

5.167 × 107 or 5.167E7

The GCF is 1.

12, 16 and 23 is one possible triplet.

Subtracting 3 each time.

Composite numbers are numbers that are not prime- that is, they are divisible by numbers besides 1 and themselves. 51 is actually divisible by 1, 3, 17, and 51, so it is composite.

51 is not a prime number: 3x17=51

31 is prime, but 51 is not as 51=3*17.

The prime numbers between 51 and 60 are 53 and 59.

41, yes. 51, no.

51 lbs = 23 kg

1 x 51 = 51 3 x 17 = 51

There are ten prime numbers between 51-100.

No two prime numbers satisfy that request.

The prime factors of 51 are 3 and 17.

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