The series follows a pattern where each term is obtained by multiplying the previous term by 3 and then adding 1. Specifically: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 2 = 41), and (41 \times 3 - 3 = 122). Following this pattern, the next term would be (122 \times 3 - 4 = 362 - 4 = 358). Therefore, the next number in the series is 365.
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
122, because it goes x2 then -1 and repeats
365 since the pattern is times three minus one
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
41 should be in between 14 and 122
multiplication pattern
41.
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
365 since the pattern is times three minus one
122, because it goes x2 then -1 and repeats
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
365.
Add 3n-1. For example 1 + 30 = 2 2 + 31 = 5 5 + 32 = 14 14 + 33 = 41
2 (+3) 5 (+9) 14 (+27) 41 (+81) 122 in this series... the difference is multiplied by 3. like 3,9,27,81,243...
41 122 365
I assume that the fifth term must be 14, and not 4...If this is the case, then the pattern is: x3, then -1 meaning that the next term will be 122.