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Q: What is the pattern rule for this pattern 1 3 2 6 5 15 14 42 41?

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multiplication pattern

Add 3n-1. For example 1 + 30 = 2 2 + 31 = 5 5 + 32 = 14 14 + 33 = 41

Start at 1. Multiply by 3. Subtract 1. Multiply by 3. Subtract 1. Repeat this pattern.

122, because it goes x2 then -1 and repeats

41 years, from 27 B.C. to 14 A.D.

n*3; n-1 {Where "n" is the previous answer starting at 1. 1, 1*3=3, 3-1=2, 2*3=6, 6-1=5, 5*3=15, 15-1=14, 14*3=42, 42-1=41.

14

Augustus ruled from c.31/27 BCE BC to 14 CE; for 45/41 years.

I assume that the fifth term must be 14, and not 4...If this is the case, then the pattern is: x3, then -1 meaning that the next term will be 122.

41 19 15 7 41 19 15 7 41 19 15 7 41 19 15 7 41-19-15-7 (104 points)

41 * 14/100 = 5.74

9999

Augustus reigned from Jan 16, 27 BC- August 19 14 AD. 41 Years

The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.

14/15 ÷ 2/9 = 21/5 or 41/5

look the consolidation strategy of Apostle Paul in Acts 14:21-22,,,Acts 15:36,,,,Acts 15:40-41

The pattern is... add 7 then subtract 4. The next two numbers would be 45 & 41.

Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.

-41

No you can not. 15 and 41 do not have a common factor

Augustus ruled for 44 years. Most historians measure the rule of Octavian (Augustus Caesar) from 27 BC to 14 AD or approximately 41 years. This is only a minor discrepancy from the first answer.

Octavian/Augustus was the first emperor of Rome and his rule lasted for 41 years, from 27 BC to 14 AC.

2.9286

The next number has to be 41; you always add the powers of three to the previous number beginning with 0. 3^0=1; 1+1=2; 3^1=3; 2+3=5; 3^2=9; 5+9=14; 3^3=27; 14+27=41 the next number would be 122 (81+41); you could also multiply the number by 3 and then substract 1. By the way: x(n)=x(n-1)+3^(x-2) ------------------------------------------------------------------------------------------------------------------- It could also be the Catalan number sequence, found by 1/(n+1) * (2n choose n), in which case the next number would be 42.

The Least Common Multiple (LCM) of 15 and 41 is 615.

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