Q: What is the percent of 44 percent out of 56?

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a decrease of 56%

31.36

MnCl2 contains one manganese (Mn) atom and two chlorine (Cl) atoms. To calculate the percent composition, divide the molar mass of each element by the molar mass of the compound and multiply by 100. The percent composition of Mn in MnCl2 is 25.41%, and the percent composition of Cl is 74.59%.

The score would be 56%

56-44 = 12

You can lose 44% which is 150*44/100 = 66. But then you must get every one correct!

100

44

44 - 56 = -12

44 x 56 = 2464

Which fraction is equal to 44/56

1.2727