Oxygen is a chemical element with the symbol O and atomic number of 8. Its percentage composition in the compound NiSO4 x 7H2O is 31.3%.
What is the percentage of oxygen to the nearest tenth in this compound NiSO4 x 7H2O?
a+ answer:62.90
NiSO4 * 7H2O NiSO4 * 7H2O
Pure water (H2O), with a pH of 7
Sodium chloride = salt Salt is a compound
There are 432 Na4 B17 O (7 in the Na2B4O7 and 10 in the hydrating H2O)20 H (in the hydrating H2O)
Atomic weight of hydrogen is 1,008. Atomic weight of oxygen is 15,999. The sum is the molar mass of H2O: 18,015 g. And 7 H2O is 126,105 g.
7
Formula: X.7H2OX is a compound
Pure water (H2O), with a pH of 7
Water, H2O is covalently bonded, but in the liquid form it does dissociate very slightly into ions. In pure water the concentration of H+ is 10-7 molar.
H2O is a covalent compound predominantly, but it spontaneously ionizes to produce about 10-7 moles per liter each of hydrogen and hydroxide ions at 25C.
The name of this compound is iodine heptafluoride.
Manganese(VI) Sulfite
H2O is a neutral compound.Its pH is 7 in 25 Celcious.
See page 7 of "Corrosion Resistance of Electroless Nickel Coatings.pdf" found at related link.
7 = neutral
h2o, because h2so4 is a strong acid and h2o is actually neutral (pH of 7)
7 it is completely neutral
molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens. So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%