22 meters
The perimeter (distance around the outside) = length + width + length + width
P = 2L + 2W
2 (4) + 2 (7) = 22
28meters
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
(4 + 1) × 2 = 10 metres
Perimeter=2(l+b) =2*6 =12m
28 square meters
24 meters Perimeter (distance around the outside) = two lengths and two widths P = 2L + 2W 2 (7) + 2(5) = 24
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
(4 + 1) × 2 = 10 metres
The area of rectangle is : 56.0
Perimeter = 2*(4m + 85cm) = 2*4.85 m = 9.7 m
7*8*4 = 224 cubic metres.
(4 + 1) × 2 = 10 metres
Perimeter=2(l+b) =2*6 =12m
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
In order to make sense of this question it is necessary to assume that the area is 28 SQUARE metres and not 28 metres as stated. Then, Length = Area/Width = 28/4 = 7m Then perimeter = 2*(Length + width) = 2*(7 + 4) = 2*11 = 22 metres.
um i think you multiply them
28 square meters