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A rectangle has two dimensions, length and width. You haven't said what the width is.

The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width.

In general, the perimeter of a rectangle is twice its length plus twice its width.

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Q: What is the perimeter of a rectangle with length 42 inches?

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The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar

2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.

Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42

The dimensions of the rectangle are 3 inches by 14 inches

The perimeter is 42 metres.

Perimeter = 168 inches so 4*length of side = 168 inches Length of side = 168/4 = 42 inches So area = 42*42 = 1764 square inches.

The area of Joseph’s rectangular homework desk is 1,008 square inches. If the length of his desk is 42 inches, how wide is his desk?

The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42

Area of rectangle: 6 times 7 = 42 square inches

The perimeter of the rectangle is 42 units

Its dimensions are 6 inches by 7 inches because 2(6+7)=26 inches and 6*7=42 square inches

Perimeter of rectangle: 16.5+4.5+16.5+4.5 = 42 units

There is insufficient information to answer this question. A rectangle with length L and width W has perimeter 2(L+W) So 2(L+W) = 42 which means L+W=21 So, given that the length should be greater than the width, any value of L such that 10.5 < L < 21 will meet the requirements. Obviously, for each value of L there will be a different value for W.

When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .

42 <insert unit> squared.

what is the perimeter of a 11cm x 10cm rectangle answer 42

None. 42 yards is a length with no width. Therefore it cannot have a perimeter.

See if the Hexagon is regular, that is, if all the sides are equal then the perimeter is 12inches x 6 as there are 6 sides for an hexagon. Therfore the answer is 72 inches.

Try a rectangle with dimensions of 6 cm and 7 cm, and see what you get.

42 square units.

Let w be the width, then 2(7 + w) = 42 or 14 + 2w = 42 or 2w = 42 - 14 or 2w = 28 w = 14

L + W = P/2 = 42 ie L = 42 - W; L = 4W + 2 so 42 - W = 4W + 2 ie 5W = 40 so width is 8 cm making length 34 cm

The perimeter of a rectangle = 2L + 2W So, from your problem we know that L = W + 27 Use this equation for the length and substitute in the perimeter equation, we get: 2(W+27) + 2W = 96 Now we rearrange and solve for W 2W + 54 + 2W = 96cm 4W + 54 -54 = 96 -54 4W = 42 W = 10.5cm, and using this value L = 10.5 + 27 = 37.5cm

There is no limit to the size of the perimeter.

width = x and length = x+3 the perimeter = x + x +( x+3) +(x + 3) = 48, solve for x 4x + 6 = 48m 4x = 42 x = 10.5m (width) x+3 = 13.5m (length)