Pentagon has 5 sides
Regular => each side 9cm
=> perimeter = 5 x 9cm = 45cm
any 2-D shape could have a perimeter of 9cm. One example is a square with sides of 9/4 cm.
Area 51.
This is not an equilateral triangle.
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
Area = 0.5*base*height Note that the given dimensions would not form a triangle
Perimeter = sum of the lengths of sides = 5* 7 cm = 35 cm
It would be 63cm. There are 7 sides and each side is 9cm so 7 times 9 is 63.
any 2-D shape could have a perimeter of 9cm. One example is a square with sides of 9/4 cm.
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
it is 81cm
9cm + 5cm + 9cm + 5cm = 28cm
ok if the perimeter is 36cm and it is a square then you know all four sides are equal 36cm / 4sides = 9cm for each side A = L * W ( both the length and width are 9cm because each side is equal ) A = 9cm * 9cm A = 81cm2
All you do is add the sides up for the perimeter. 12 + 10 + 9 = 31
31 centimeters
If you're talking about a five sided figure, just add up your figures.
you cant do that becaues to get a perrimetr you need to add all the sides. when you do that it wll either be less then 9 or more then 9 in conclusion you cant get a shape that has a perimeter of