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1 Let the height be x+1.75 and the base be x

2 1837.5 sq mm is the same as 18.375 sq cm

3 0.5*(x+1.75)*x = 18.375 => x2+1.75x-36.75 = 0

4 Using the quadratic equation gives x a positive value of 5.25

5 Therefore: height = 7 cm and base = 5.25 cm

6 Using Pythagoras: hypotenuse = 8.75 cm

7 Perimeter: 8.75+7+5.25 = 21 cm

Q: What is the perimeter of a right angle triangle whose height is greater than its base by 1.75 cm with an area of 1837.5 square mm showing work to the nearest cm?

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Let the sides be s:- If: 0.5*s squared*sin(60 degrees) = 97.428 Then: s = square root of 97.428*2/sin(60 degrees) => 15.00001094 Perimeter: 3*15 = 45 cm

These are basically the steps: * Use the formula for the area of a triangle to calculate the height. * Use the height and half the base to calculate the lateral sides. Use the Pythagorean Theorem. (It helps to draw a sketch, to visualize the situation.) * Add the three sides to get the perimeter.

Such a triangle would be impossible to construct with the given 3 dimensions because in order to construct a triangle the sum of its 2 shortest sides must be greater than the length of its longest side.

Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.

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Let the sides be s:- If: 0.5*s squared*sin(60 degrees) = 97.428 Then: s = square root of 97.428*2/sin(60 degrees) => 15.00001094 Perimeter: 3*15 = 45 cm

what is the difination of showing the greater class

These are basically the steps: * Use the formula for the area of a triangle to calculate the height. * Use the height and half the base to calculate the lateral sides. Use the Pythagorean Theorem. (It helps to draw a sketch, to visualize the situation.) * Add the three sides to get the perimeter.

Such a triangle would be impossible to construct with the given 3 dimensions because in order to construct a triangle the sum of its 2 shortest sides must be greater than the length of its longest side.

it should be a triangle with no red showing

value

Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.

1 Let its height be x+1.45 and its base be x2 So: 0.5*(x+1.45)*x = 12.615 multiply both side by 23 Therefore: x2+1.45x-25.23 = )4 Using quadratic equation formula gives x a positive value of 4.355 It follows: height = 5.8 and base = 4.356 Using Pythagoras: hypotenuse = 7.257 Perimeter: 5.8+4.35+7.25 =17.4 cm

according to the formulae : area of triangle = (1/2) x base of triangle x height 54=(1/2)xBxH B x H = 108 now we have to factorize it.. factors can be.. (12,9),(27,4)(18,6)(36,3) now its given perimeter=36 we have to check two condition for the tringle to be right angle triangle sum of two sides > third side sum of the square of the two sides of triangle(shorter sides)= square of the third side. only one factor (12,9) satisfies both the conditions.. so the third side comes out to be 36-(12+9)=15 so the sides are...12,9,15. that's your answer..

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There cannot be a proof because the statement need not be true.

Suppose the base is B. Then height is B+2.5 Therefore Area = 0.5*Base*Height implies that 37.5 = 0.5*B*(B+2.5) or 0.5B2 + 1.25B - 37.5 = 0 which implies that B = 7.5 m (the other root of the quadratic is negative). Then H = 7.5+2.5 = 10 m By Pythagoras, the third side is sqrt(7.52 + 102) = sqrt(156.25) = 12.5 m So, the perimeter is 7.5 + 10 + 12.5 = 30 metres