Add all the sides of the irregular figure to the obtain the perieter.
In the this particular case the permeter will be 2+3+4+9 =18 cms.
10cm 2l + 2w 4+6=10cm
Mean = sum(X)/n = 15cm/5 = 3cm
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It is impossible to answer this question because the question could refer to an object in 7-dimensional hyperspace or it could be an irregular heptagon (or other possible shapes in 3, 4 5 or 6 dimensions). In anything but 7-d space, its exact shape is indeterminate and so the area cannot be calculated. To understand the indeterminacy, a 2cm + 2cm + 2cm + 2cm shape could be a rhombus or a square, and these will have different areas. Without the angles, there is no way of knowing which.
463.2 grams.
Assuming the measurements given are the lengths of the sides of a hexagon, the perimeter is 2 + 2 + 2 + 3 + 5 + 11 = 25 cm.
10cm 2l + 2w 4+6=10cm
2X3=6+(4X9)= 42 42 square centimeters
Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
An isosceles triangle
it is "1 == 2"
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
Assuming this is a rectangular block, you are supposed to multiply the three numbers.
2cm*5cm*3cm=30cm3The volume of the cuboid: 2*5*3 = 30 cubic cm
2x3x2=12cm3
It could be 3cm by 2cm in size.
14cm