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Q: What is the period of a pendulum that takes 48 seconds to complete 16 cycles?

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The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.

no. it affects the period of the cycles.

Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2

assume the cycle starts when the pendulum is at the top left. It will go to the bottom, to the top right, to the bottom and then back to the top left. The time it takes it to do this is the period. 60 seconds in a minute and 60 divide by 15 is 4. Therefore you will have 4 cycles.

Time period per oscillation=32/ 20=1.6 sec per oscillation.

Related questions

The period of a pendulum is the time it takes to complete one full swing back and forth. In this case, the period of the pendulum is 10 seconds (5 seconds for each half of the swing).

Actually, the time for a complete to-and-fro swing of a pendulum is called its period, which is the time taken to complete one full cycle of motion. The frequency of a pendulum is the number of cycles it completes in a given time, usually measured in hertz (cycles per second).

The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.

A complete back and forth vibration, also known as a full oscillation, for a pendulum with a period of 1.5 seconds would take a total time of 3 seconds. This time includes both the movement to one side and back to the starting point.

The period of an oscillating pendulum is typically measured in seconds (s) or seconds per cycle. The period is the time it takes for the pendulum to complete one full oscillation.

no. it affects the period of the cycles.

Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2

The period of the mass on a spring can be calculated by dividing the total time taken (8 seconds) by the number of cycles completed (5 cycles). Therefore, the period of the mass on the spring is 1.6 seconds per cycle.

This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.

The period of a pendulum can be calculated using the equation T = 2π√(l/g), where T is the period in seconds, l is the length of the pendulum in meters, and g is the acceleration due to gravity (9.81 m/s^2). Substituting the values, the period of a 0.85m long pendulum is approximately 2.43 seconds.

The frequency of the pendulum is 1/3 Hz, as frequency is the number of complete cycles (swings) per second. Since it completes one cycle every 3 seconds, the frequency is the reciprocal of the time period, which is 1/3 Hz.

For a simple pendulum: Period = 6.3437 (rounded) seconds