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What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?
Wiki User
∙ 12y ago
Points: (-2, 5) and (-8, -3)
Midpoint: (-5, 1)
Slope: 4/3
Perpendicular slope: -3/4
Use: y-1 = -3/4(x--5)
Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
Wiki User
∙ 12y ago
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How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
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Find the equation of the line joining the point -76-3 and 7-63?
I'm assuming the points are (-76, -3) and (7, -63). If that's the case then the equation can be found by the following. (1) First find the slope of a line between these two point, m: m = (y1 - y2)/(x1 - x2) = (-3 - -63) / (-76 - 7) = - 60/83 (2) The equation for a line is y = mx + b, since we have the slope m already, use one of the points listed to solve for the intercept b. (I used the first one: -76, -3) -3 = -60/83*(-76) + b -3 = 4560/83 + b b = -4809/83 So the equation of the line joining these two point is: Y = (-60/83)X - (4809/83)
The segment joining the midpoints of two sides of a triangle is the?
midsegment
What is the equation of the circle through -2 -4 60 and 15?
Given any two points, there are infinitely many coplanar circles that can go through the two points. And then each circle can be rotated through infinitely many planes about the straight line joining those two points. So as stated, there is not the slightest hope of pinning down an answer.
What is a characteristic of a perpendicular bisector?
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the difference between a perpendicular line and a perpendicular bisector?
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
What is the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
What are the values of a and b given that y plus 4x equals 11 is the perpendicular bisector equation of the line joining a 2 to 6 b?
Their values work out as: a = -2 and b = 4
What is the locus of points equidistant from two points?
The perpendicular bisector of the straight line joining the two points.
What describes the Locus of all points that are equidistant from 2 lines?
The perpendicular bisector of the line joining the two points.
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
What is the equation and its perpendicular bisector equation of the line joining the points of 1 2 and 3 4 showing work?
1 Points: (1, 2) and (3, 4) 2 Slope: (2-4)/(1-3) = 1 3 Perpendicular slope: -1 4 Midpoint: (1+3)/2 and (2+4)/2 = (2, 3) 5 Equation: y-2 = 1(x-1) => y = x+1 6 Bisector equation: y-3 = -1(x-2) => y = -x+5
What is the locus of points equidistant from two points A and B that are 8 meters apart?
It is the perpendicular bisector of AB, the line joining the two points.
What are the values of p and q if y plus 4x equals 11 is the perpendicular bisector equation of the line joining p 2 to 6 q?
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
