Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
Their values work out as: a = -2 and b = 4
The perpendicular bisector of the straight line joining the two points.
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
The perpendicular bisector of the line joining the two points.
It is the perpendicular bisector of AB, the line joining the two points.
A line joining any vertex to the midpoint of the opposite side. Because of the properties of an equilateral triangle, this line may be described as the median, the perpendicular bisector of a side or an angle bisector.
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
They must be equidistant from the point of bisection which is their midpoint and works out that a = -2 and b = 4 Sketching the equations on the Cartesian plane will also help you in determining their values
The key stages of the work are the following:1) Find the slope for the line that joins the given points.2) Divide -1 by this slope to get the slope of the perpendicular line.3) Find the midpoint (calculate the averages of the x-coordinates and of the y-coordinates).4) Use the point-slope equation of the line to find a line with the desired slope, that goes through the desired point.Another Answer:-Points: (-7, -3) and (-1, -4)Mdpoint: (-4,-3.5)Slope: -1/6Perpendicular slope: 6Equation: 6y = -x-25 or as x+6y+25 = 0Perpendicular bisector equation: y = 6x+20.5 or as 6x-y+20.5 = 0
1 Points: (1, 2) and (3, 4) 2 Slope: (2-4)/(1-3) = 1 3 Perpendicular slope: -1 4 Midpoint: (1+3)/2 and (2+4)/2 = (2, 3) 5 Equation: y-2 = 1(x-1) => y = x+1 6 Bisector equation: y-3 = -1(x-2) => y = -x+5
If the points are (b, 2) and (6, c) then to satisfy the straight line equations it works out that b = -2 and c = 4 which means that the points are (-2, 2) and (6, 4)
First find the midpoint of (-2, 5) and (-8, -3) which is (-5, 1) Then find the slope of (-2, 5) and (-8, -3) which is 4/3 Slope of the perpendicular bisector is the negative reciprocal of 4/3 which is -3/4 Now form an equation of the straight line with a slope of -3/4 passing through the point (-5, 1) using the formula y-y1 = m(x-x1) The equation works out as: 3x+4y+11 = 0
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
The slope of the line is 1/4 So the values are t = -2 and v = 4 Because they satisfy the equation: (v-2)/6-t = 2/8 = 1/4
(s, 2s) and (3s, 8s); s ≠ 0, otherwise we have just one point, the origin.First, find the slope of the non-vertical line joining the two given points.(2s - 8s)/(s - 3s) = -6s/-2s = 3The slope of the perpendicular line must be the negative reciprocal of 3. Therefore it is -1/3.Since the line is a perpendicular bisector, it must passes through the midpoint[(s +3s)/2, (2s + 8s)/2] = (2s, 5s).Since we know the slope and one point on the line, we can write the point-slope form of the equation,y - 5s = -(1/3)(x - 2s).If you want, you can turn the equation into the slope-intercept form or the standard form.Another Answer:-It is: x+3y-17s = 0 in its general form
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
Let P = (7, 3) and Q = (-6, 1) Then mid point of PQ = ((7-6)/2, (3+1)/2) = (1/2, 2) Also, gradient of PQ = (3 - 1)/(7 + 6) = 2/13 So the gradient of the perpendicular = -13/2 Therefore the required line passes through the point (1/2, 2) and has gradient -13/2 and so its equation is (y - 2) = -13/2*(x - 1/2) or 4y - 8 = -26x + 13 that is 26x + 4y - 21 = 0
The system of two point charges plus q and -q constitutes an electric dipole.In the case of an electric dipole ,the resultant field is parallel to the line joining the two charges at 1.any point on the line joining the charges 2.any point on the perpendicular bisector of the line joining the two charges.