Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0
Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16
Points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 or 0.5 Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Equation: y-2 = -13/2(x-0.5) => 2y-4 = -13(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 13x+2y -10.5 = 0
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
The perpendicular bisector of a line has a gradient (m') which is the negative reciprocal of the gradient (m) of the line, and passes through the mid-point of the line.The equation of a line with gradient m through a point (x0, y0) has an equation of the form:y - y0 = m(x - x0)The gradient m of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y / change_in_x = (y1 - y0) / (x1 - x0)Thus the line through (p, q) and (7p, 3q) has gradient:m = (3q - q) / (7p - p) = 2q / 6p = q/3pand the perpendicular bisector has gradient:m' = -1 / m = -1 / (q/3p) = -3p/qThe midpoint of the line through (p, q) and (3p, 3q) is:midpoint = ((p + 7p)/2), (q + 3q)/2) = (4p, 2q)Thus the perpendicular bisector of the line between (p, q) and (7p, 3q) has equation:y - 2q = -3p/q (x - 4p)â†’ qy - 2qÂ² = -3px + 12pÂ²â†’ qy + 3px = 12pÂ² + 2qÂ²Additional Information:-Final answer in its general form: 3px+qy-12p^2-2q^2 = 0
no a equilateral triangle does not have any perpendicular sides because the lines are joined together.
The equation of a line through point (x0, y0) with gradient m is given by:y - y0 = m(x - x0)The gradient (m) of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)→ The equation of the line between (11, 13) and (17, 19) is given by:y - 13 = (19-13)/(17-11) (x - 11)→ y - 13 = 6/6 (x - 11)→ y - 13 = x - 11→ y = x + 2and its gradient is m = 1.The gradient (m') of a line perpendicular to a line with gradient m is such that mm' = -1, ie m' = -1/m→ The gradient of the perpendicular line to the line between (11, 13) and (17, 19) has gradient m' = -1/1 = -1.The perpendicular bisector goes through the point midway between (11, 13) and (17, 19) which is given by the average of the x and y coordinates: ((11+17)/2, (13+19)/2) = (14, 16)Thus the perpendicular bisector of the line joining (11, 13) to (17,19) is given by:y - 16 = -1(x - 14)→ y - 16 = -x + 14→ y + x = 30Which in its general form is: x+y-30 = 0
Draw a straight line and with compass mark off two joined arcs above and below the line and then join the arcs together which will produce a perpendicular line.
None. A perpendicular line is two lines joined together to make a right angle(90degrees). A hexagon has no right angles so there are no perpendicular lines. None, by definition perpendicular means a 90 degree intersection of two lines. A hexagon's intersections are only 60 degrees.
It is a closed four-sided shape with one pair of parallel sides, joined at only one end by a line which is perpendicular to both.
The answer to this probably depends on (a) the font and (b) wheter the uppercase letter or the lowercase letters are considered. In this particular font, in uppercase B D E F H I K L M N P R and T all have perpendicular segments, G has a short perpendicular segment J has a perpendicular segment which ends in a curve U has two perpendicular segments joined by a curve and in lowercase b d h i k l m n p r and u all have perpendicular segments a f g j and t all have perpendicular segments with curved parts.
C6H12O6 + C6H12O6 = C12H22O11 + H2O (as a result of dehydration synthesis)
Many letters of the English alphabet have perpendicular lines. Perpendicular lines are like two lines making one corner of a square. So any letter that has two lines joined like the corner of a square has perpendicular lines.These letters have right angles: E, F, f, H, I, L T, t, and sometimes X, x.Keep in mind that the angles of the lines making the letters is effected by the font and whether or not the letter is italicized. For example, E is made of three perpendicular lines, but this 'E' has no perpendicular lines.
No country joined in 1954. Greece and Turkey joined in 1952 and West Germany joined in 1955.
Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.Yes. It joined in 2004.
who joined the union
A mathematical phrase containing numbers and operations is called an expression. Expressions can be joined together with an equals sign to form an equation.
An equation consists of two expressions joined by an '=' sign. If there is only one variable, you can usually solve the equation (find the value of the variable that makes the equation true). Example: 3x + 5 = 11: the solution is 2. (The techniques for finding the solution are a major part of algebra.) Check that 3(2) +5 = 6+5 = 11.
No countries joined in 2003. 10 joined in 2004 and prior to that, the last time countries joined was in 1995.