Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0
Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16
Points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 or 0.5 Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Equation: y-2 = -13/2(x-0.5) => 2y-4 = -13(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 13x+2y -10.5 = 0
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
The perpendicular bisector of a line has a gradient (m') which is the negative reciprocal of the gradient (m) of the line, and passes through the mid-point of the line.The equation of a line with gradient m through a point (x0, y0) has an equation of the form:y - y0 = m(x - x0)The gradient m of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y / change_in_x = (y1 - y0) / (x1 - x0)Thus the line through (p, q) and (7p, 3q) has gradient:m = (3q - q) / (7p - p) = 2q / 6p = q/3pand the perpendicular bisector has gradient:m' = -1 / m = -1 / (q/3p) = -3p/qThe midpoint of the line through (p, q) and (3p, 3q) is:midpoint = ((p + 7p)/2), (q + 3q)/2) = (4p, 2q)Thus the perpendicular bisector of the line between (p, q) and (7p, 3q) has equation:y - 2q = -3p/q (x - 4p)â†’ qy - 2qÂ² = -3px + 12pÂ²â†’ qy + 3px = 12pÂ² + 2qÂ²Additional Information:-Final answer in its general form: 3px+qy-12p^2-2q^2 = 0
no a equilateral triangle does not have any perpendicular sides because the lines are joined together.
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
It works out as an isosceles triangle
The equation of a line through point (x0, y0) with gradient m is given by:y - y0 = m(x - x0)The gradient (m) of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)→ The equation of the line between (11, 13) and (17, 19) is given by:y - 13 = (19-13)/(17-11) (x - 11)→ y - 13 = 6/6 (x - 11)→ y - 13 = x - 11→ y = x + 2and its gradient is m = 1.The gradient (m') of a line perpendicular to a line with gradient m is such that mm' = -1, ie m' = -1/m→ The gradient of the perpendicular line to the line between (11, 13) and (17, 19) has gradient m' = -1/1 = -1.The perpendicular bisector goes through the point midway between (11, 13) and (17, 19) which is given by the average of the x and y coordinates: ((11+17)/2, (13+19)/2) = (14, 16)Thus the perpendicular bisector of the line joining (11, 13) to (17,19) is given by:y - 16 = -1(x - 14)→ y - 16 = -x + 14→ y + x = 30Which in its general form is: x+y-30 = 0
The given coordinates when plotted and joined together on the Cartesian plane appears to form a scalene triangle.
Draw a straight line and with compass mark off two joined arcs above and below the line and then join the arcs together which will produce a perpendicular line.
The Cartesian plane has an horizontal number line called the x axis and a vertical number line called the y axis. Both axes are perpendicular to each other and bisect each other at the point of origin which is at (0, 0) When plotting points the x value comes first followed by the y value as for example the coordinates of say (5, 7) means to move 5 units horizontally along the x axis and then 7 units up vertically and marking the spot. This then is the coordinate of (5, 7) and other coordinates are plotted in the same way marking the spot each time. If it's a straight line equation then the plotted markings should form a straight line when joined together.
None. A perpendicular line is two lines joined together to make a right angle(90degrees). A hexagon has no right angles so there are no perpendicular lines. None, by definition perpendicular means a 90 degree intersection of two lines. A hexagon's intersections are only 60 degrees.
It is a closed four-sided shape with one pair of parallel sides, joined at only one end by a line which is perpendicular to both.
If you mean: 5x-2y = 20 then the x and y intercepts are (4, 0) and (0, -10) respectively and when joined together on the Cartesian plane forms a straight line.
The answer to this probably depends on (a) the font and (b) wheter the uppercase letter or the lowercase letters are considered. In this particular font, in uppercase B D E F H I K L M N P R and T all have perpendicular segments, G has a short perpendicular segment J has a perpendicular segment which ends in a curve U has two perpendicular segments joined by a curve and in lowercase b d h i k l m n p r and u all have perpendicular segments a f g j and t all have perpendicular segments with curved parts.
C6H12O6 + C6H12O6 = C12H22O11 + H2O (as a result of dehydration synthesis)
Many letters of the English alphabet have perpendicular lines. Perpendicular lines are like two lines making one corner of a square. So any letter that has two lines joined like the corner of a square has perpendicular lines.These letters have right angles: E, F, f, H, I, L T, t, and sometimes X, x.Keep in mind that the angles of the lines making the letters is effected by the font and whether or not the letter is italicized. For example, E is made of three perpendicular lines, but this 'E' has no perpendicular lines.
Answer:when a join condition is omited when getting result from two tables then that kind of query gives us Cartesian product, in which all combination of rows displayed. All rows in the first table is joined to all rows of second table...Hope this answer helps!Inclus - We provide individual and corporate trainingEducate, Learn & Serve
No country joined in 1954. Greece and Turkey joined in 1952 and West Germany joined in 1955.