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Points: (p, q) and (7p, 3q)

Midpoint: (4p, 2q)

Slope: q/3p

Perpendicular slope: -3p/q

Perpendicular bisector equation:-

=> y-2q = -3p/q(x-4p)

=> qy-2q^2 = -3p(x-4p)

=> qy-2q^2 = -3px+12p^2

=> qy = -3px+12p^2+2q^2

In its general form: 3px+qy-12p^2-2q^2 = 0

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โˆ™ 2016-03-24 14:16:29
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Q: What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
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