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What is the perpendicular bisector equation of the line segment joined by the points -2 4 and -4 8?
Wiki User
∙ 6y ago
Points: (-2, 4) and (-4, 8)
Midpoint: (-3, 6)
Slope: -2
Perpendicular slope: 1/2 or 0.5
Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is x - 2y + 15 = 0.
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What is the perpendicular bisector equation of the line joined by the points of -1 3 and -2 -5?
Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16
What is another way to say joined?
connected
How many ways can you arrange 4 squares joined along an edge?
seven
How is tessellation related to math?
Polygons will tessellate if when joined together there is no gaps or overlaps
Does 5 hexiamonds joined together have line symmetry true or false?
no i don't think
What is the perpendicular bisector equation of the line joined by the points -2 5 and -8 -3 on the Cartesian plane?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0
What is the perpendicular bisector equation of the line joined by the points of -1 3 and -2 -5?
Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16
What is the perpendicular bisector equation of the line joined by the points of h k and 3h -5k on the coordinated grid?
8
What is the perpendicular bisector equation of the line joined by the points of s 2s and 3s 8s?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y-5s = -1/3(x-2s) => 3y-15s = -x+2s => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of the line joined by the points of 7 3 and -6 1?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Equation: y-2 = -13/2(x-0.5) => 2y-4 = -13(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 13x+2y -10.5 = 0
What is the perpendicular bisector equation of the line joined by the points h k and 3h -5k showing work?
8
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q showing work and final answer in its general form?
The perpendicular bisector of a line has a gradient (m') which is the negative reciprocal of the gradient (m) of the line, and passes through the mid-point of the line.The equation of a line with gradient m through a point (x0, y0) has an equation of the form:y - y0 = m(x - x0)The gradient m of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y / change_in_x = (y1 - y0) / (x1 - x0)Thus the line through (p, q) and (7p, 3q) has gradient:m = (3q - q) / (7p - p) = 2q / 6p = q/3pand the perpendicular bisector has gradient:m' = -1 / m = -1 / (q/3p) = -3p/qThe midpoint of the line through (p, q) and (3p, 3q) is:midpoint = ((p + 7p)/2), (q + 3q)/2) = (4p, 2q)Thus the perpendicular bisector of the line between (p, q) and (7p, 3q) has equation:y - 2q = -3p/q (x - 4p)→ qy - 2q² = -3px + 12p²→ qy + 3px = 12p² + 2q²Additional Information:-Final answer in its general form: 3px+qy-12p^2-2q^2 = 0
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
How many letters of the alphabet have perpendicular line segments?
The answer to this probably depends on (a) the font and (b) wheter the uppercase letter or the lowercase letters are considered. In this particular font, in uppercase B D E F H I K L M N P R and T all have perpendicular segments, G has a short perpendicular segment J has a perpendicular segment which ends in a curve U has two perpendicular segments joined by a curve and in lowercase b d h i k l m n p r and u all have perpendicular segments a f g j and t all have perpendicular segments with curved parts.
Does an equilateral triangle have any perpendicular sides?
no a equilateral triangle does not have any perpendicular sides because the lines are joined together.
What is the perpendicular bisector equation of the line joined by the points 11 13 and 17 19 showing work and answer?
The equation of a line through point (x0, y0) with gradient m is given by:y - y0 = m(x - x0)The gradient (m) of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)→ The equation of the line between (11, 13) and (17, 19) is given by:y - 13 = (19-13)/(17-11) (x - 11)→ y - 13 = 6/6 (x - 11)→ y - 13 = x - 11→ y = x + 2and its gradient is m = 1.The gradient (m') of a line perpendicular to a line with gradient m is such that mm' = -1, ie m' = -1/m→ The gradient of the perpendicular line to the line between (11, 13) and (17, 19) has gradient m' = -1/1 = -1.The perpendicular bisector goes through the point midway between (11, 13) and (17, 19) which is given by the average of the x and y coordinates: ((11+17)/2, (13+19)/2) = (14, 16)Thus the perpendicular bisector of the line joining (11, 13) to (17,19) is given by:y - 16 = -1(x - 14)→ y - 16 = -x + 14→ y + x = 30Which in its general form is: x+y-30 = 0
