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What is the perpendicular distance from the point 7 5 to the staight line equation 3x plus 4y -16 equals 0 showing key stages of work?
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∙ 10y ago
Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Both equations intersect at: (4, 1) Perpendicular distance: square root of (7-4)2+(5-1)2 = 5
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∙ 10y ago
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What is the perpendicular distance from the coordinate of 2 5 that meets the staight line of y equals 7x plus 13 at right angles on the Cartesian plane showing all work and answer to 3 decimal places?
Coodinate: (2, 5) Equation: y = 7x+13 Slope: 7 Perpendicular slope: -1/7 Perpendicular equation: 7y = -x+37 Both equations intersect at: (-1.08, 5.44) Perpendicular distance: square root of [(-1.08-2)^2+(5.44-5)^2] = 3.111 to 3 d.p.
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